Since points are collinear, then the pass through same line , it means their slope issame
m=\(\frac{y2-y1}{x2-x1}\)
for (a, 0) and (1, 1)
m=\(\frac{1-a}{1}\)
for (1, 1) and (0, b)
m=\(\frac{-1}{b-1}\)
since both slope is sameso
\(1-a\) =\(\frac{-1}{b-1}\)
a=\(\frac{1}{b-1}\)+1
a=\(\frac{b}{b-1}\)
Hence,C
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m=\(\frac{y2-y1}{x2-x1}\)
for (a, 0) and (1, 1)
m=\(\frac{1-a}{1}\)
for (1, 1) and (0, b)
m=\(\frac{-1}{b-1}\)
since both slope is sameso
\(1-a\) =\(\frac{-1}{b-1}\)
a=\(\frac{1}{b-1}\)+1
a=\(\frac{b}{b-1}\)
Hence,C
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