desertEagle wrote:
Bunuel wrote:
For which values of\(x\) is\( p >q\) if\( 4x + p = 6y +q\) is the only constraint?
(1)\( y =3\)
(2)\( y >2\)
Are You Up For the Challenge: 700 LevelQuestions
(1)\( y =3\)
(2)\( y >2\)
Are You Up For the Challenge: 700 LevelQuestions
\( p >q\) =>\( p -q\) --- 1
\( 4x + p = 6y +q\)
\( p - q = 6y -4x\) ---- 2
to satisfy 1, 2 becomes
\( 6y - 4x >0\)
\( 3y > 2x\) ---3
(1)\( y =3\)
using3
\( x<9/2\) --- so we know values of x ---- Sufficient
(2)\( y >2\)
for different values of y, we
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