Since each worker works with the other 14 workers once, the total number of days 1 worker will work in pairs will be 14.
Also, after the above 14 days of work, each worker will work again for the next 5 days with all the other workers.
Thus, the total number of days each worker worked = 19.
Let the efficiency of the 15 workers be a, b, c,.......o
Total work = 19(a+b+c+.....+o)
If all workers work together, total work done in a day = (a+b+c+.....+o)
Time taken by all the workers to finish
...
Also, after the above 14 days of work, each worker will work again for the next 5 days with all the other workers.
Thus, the total number of days each worker worked = 19.
Let the efficiency of the 15 workers be a, b, c,.......o
Total work = 19(a+b+c+.....+o)
If all workers work together, total work done in a day = (a+b+c+.....+o)
Time taken by all the workers to finish
...
