Total number of arrangements: 4*3*2*1= 24
If we have to keep 'A' at 2nd place, no. of combinations then would be: 3*1*2*1= 6
Probability of A being at its original palce is 6/24=1/4
If we have to keep 'A' at 2nd place, no. of combinations then would be: 3*1*2*1= 6
Probability of A being at its original palce is 6/24=1/4
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