RenB wrote:
If x is an integer and y is a non-negative integer such that 4x-3y = 36 and ly - 3| < 16, then how many ordered pairs (x, y) satisfy the given conditions?
A. 2
B. 3
C. 4
D. 5
E.6
Given
\( |y - 3| <16\)
\( -16 < y - 3 <16\)
Adding three on both sides of the equation
\( -16 + 3 < y - 3 + 3 < 16 +3\)
\( -13 < y <19\)
\( 4x-3y =36\)
\( 3y = -36 + 3x +x\)
Divide by 3 on both sides of the equality
\( y = -12 + x +\frac{x}{3}\)
The question premise mentions that y is an integer. Hence,
x = 3 ➜ y = -12 + 3 + 1 = -8
Further values can be found as shown below-
Attachment:
Screenshot 2023-09-19 112748.jpg
OptionD
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Statistics : Posted by gmatophobia • on 18 Sep 2023, 21:04 • Replies 2 • Views 68
