The method that i have used as described in the attachment below :
Consider the distance between A and B as D.
Speed of P as x Kmph and Q as y Kmph.
Now keeping time as constant for the first meetup :
D-40/x = 40/y
From this we derive the ratio of the speeds :
D-40/ 40 = x/y.
Now moving to the next step, reversing the direction:
Distance that Q traveled post meetup = 40 + D - 20 Km
Distance that P traveled post meetup = D - 40 + 20 Km
So here again keeping the time as constant and reversing the speeds we can say :
D-20/40 = D+20/D-40
Solving the same we get D = 100.
Hence IMO A
Attachments File comment: Basic Solution
![Basic Solution / TSD 1.png TSD 1.png]()
TSD 1.png [ 337.95 KiB | Viewed 2 times ]
Consider the distance between A and B as D.
Speed of P as x Kmph and Q as y Kmph.
Now keeping time as constant for the first meetup :
D-40/x = 40/y
From this we derive the ratio of the speeds :
D-40/ 40 = x/y.
Now moving to the next step, reversing the direction:
Distance that Q traveled post meetup = 40 + D - 20 Km
Distance that P traveled post meetup = D - 40 + 20 Km
So here again keeping the time as constant and reversing the speeds we can say :
D-20/40 = D+20/D-40
Solving the same we get D = 100.
Hence IMO A
Attachments File comment: Basic Solution
TSD 1.png [ 337.95 KiB | Viewed 2 times ]
Statistics : Posted by IshanSaini • on 19 Sep 2023, 10:45 • Replies 2 • Views 201











