ArtemNYC wrote:
Bunuel wrote:
If \(x \gt 1\) and \(y \gt 1\), is \(x \gt y\)?
(1) \(\sqrt{x} \gt y\)
(2) \(\sqrt{y} \lt x\)
(1) \(\sqrt{x} \gt y\)
(2) \(\sqrt{y} \lt x\)
Let's say x=4 and y=3, so is the first condition still fine and sufficient?
x = 4 and y = 3 does not satisfy \(\sqrt{x} \gt y\).
Statistics : Posted by Bunuel • on 16 Sep 2014, 00:14 • Replies 12 • Views 75826
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