Problem Solving (PS) | Re: If a = 3^3*2^9, b = 3^6 *7^3, c = 2^6*5^3, which of the following is

a = 3^3 × 2^9
b = 3^6 × 7^3
c = 2^6 × 5^3

If we raise each of the above positive numbers to the power of 1/3, the order of the resulting numbers will correspond to the order of the original numbers.

a^(1/3) = (3^3 × 2^9)^(1/3) = 3 × 2^3 = 24
b^(1/3) = (3^6 × 7^3)^(1/3) = 3^2 × 7 = 63
c^(1/3) = (2^6 × 5^3)^(1/3) = 2^2 × 5 = 20

Since b^(1/3) > a^(1/3) > c^(1/3), we have:

b > a > c

Answer: B

Statistics : Posted by JeffTargetTestPrep • on 27 Jun 2022, 19:15 • Replies 5 • Views 1210

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