If \(f(x) = \frac{x^4 - 1}{x^2}\), what is \(f(\frac{1}{x})\) in terms of \(f(x)\)?
A. \(f(x)\)
B. \(-f(x)\)
C. \(\frac{1}{f(x)}\)
D. \(-\frac{1}{f(x)}\)
E. \(2f(x)\)
\(f(\frac{1}{x}) = \)
\(=\frac{\frac{1}{x^4} - 1}{\frac{1}{x^2} } = \)
\(=(\frac{1}{x^4} - 1)*x^2 = \)
\(=\frac{1}{x^2} - x^2 = \)
\(=\frac{1 - x^4}{x^2} = \)
\(=-\frac{x^4 - 1}{x^2} = \)
\(=-f(x)\).
Answer: B
A. \(f(x)\)
B. \(-f(x)\)
C. \(\frac{1}{f(x)}\)
D. \(-\frac{1}{f(x)}\)
E. \(2f(x)\)
\(f(\frac{1}{x}) = \)
\(=\frac{\frac{1}{x^4} - 1}{\frac{1}{x^2} } = \)
\(=(\frac{1}{x^4} - 1)*x^2 = \)
\(=\frac{1}{x^2} - x^2 = \)
\(=\frac{1 - x^4}{x^2} = \)
\(=-\frac{x^4 - 1}{x^2} = \)
\(=-f(x)\).
Answer: B
Statistics : Posted by Bunuel • on 19 Nov 2007, 10:02 • Replies 3 • Views 9139









