Bunuel wrote:
If \(n\) is the first of two consecutive odd integers, and if the difference of their squares is 120, which of the following equations can be used to find their values?
(A) \((1+n)^2-n^2=120\)
(B) \(n^2-(n+2)^2=120\)
(C) \([(n+2)-n]^2=120\)
(D) \(n^2-(n+1)^2=120\)
(E) \((n+2)^2-n^2=120\)
n is the first odd integer
n+2 is the second odd integer
the difference of their squares is 120
\((n+2)^2-n^2=120\)
Statistics : Posted by coucoudanger • on 19 Oct 2023, 01:30 • Replies 2 • Views 217










