[b] equates the least integer greater than or equal to b, which in everyday language means that [b] rounds UP to the next integer, if it is not an integer. For example, [2.5] = 3.
So the question is, is -1< \(2b\leq{0}\)
1) -1 < \(b\leq{0}\)
Not sufficient, because 2b could move to be less than -1, with 2 increasing the magnitude of the term.
2) -1 < \(3b\leq{0}\)
If 3b is between -1 and 0, then B itself has to be between -1 and 0. Dividing out the 3 would only move it closer to 0
Sufficient
B
So the question is, is -1< \(2b\leq{0}\)
1) -1 < \(b\leq{0}\)
Not sufficient, because 2b could move to be less than -1, with 2 increasing the magnitude of the term.
2) -1 < \(3b\leq{0}\)
If 3b is between -1 and 0, then B itself has to be between -1 and 0. Dividing out the 3 would only move it closer to 0
Sufficient
B
Statistics : Posted by DanTheGMATMan • on 26 Oct 2023, 00:32 • Replies 1 • Views 68
