Problem Solving (PS) | Re: If 2x^5 14x^4 + 31x^3 64x^2 + 19x + 130 = 0, then which of the fol

Since the polynomial can't be reduced from its order of 5, since no power of X can be factored out, it must have 5 roots.

The roots must multiply to equal 130.

The prime factors of 130 are

2,13 and 5.

The remaining 2 factors must be plus or minus 1.

1 appears among the answer choices but that choice can be quickly eliminated upon simple examination.

Only 5 appears among the remaining answer choices

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Statistics : Posted by Regor60 • on 09 Mar 2020, 03:18 • Replies 9 • Views 5221

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