Kimberly77 wrote:
Bunuel wrote:
OfficialSolution:
What is the value of integer\(k\)?
(1)\(2^k=1\) .
If a base is neither -1 nor 1, then for exponentiation to yield 1, the exponent must be 0. Consequently, it follows that\( k =0\) . Sufficient.
(2)\(1^k=1\) .
This equation holds true for any value of\(k\) . Not sufficient.
Answer:A
What is the value of integer\(k\)?
(1)\(2^k=1\) .
If a base is neither -1 nor 1, then for exponentiation to yield 1, the exponent must be 0. Consequently, it follows that\( k =0\) . Sufficient.
(2)\(1^k=1\) .
This equation holds true for any value of\(k\) . Not sufficient.
Answer:A
HiBunuel , St 1 given base is 1 but you stated that If a base is neither -1 nor 1, then for exponentiation to yield 1, the exponent must be 0.
A bit confused. Could you help clarify?
Also can\(2^k=2^0\) here?
\(2^k=1\)
OR\(2^k=1^1\)
Therefore St 1 is not sufficient, as K can be 0/1. Not sure what I missed?
Thanks
I don't get your question!
In statement (1), how is the base 1? It's 2! Also,\(2^k=1\) implies that k = 0:\(2^0=1\) . How can k be 1?\(2^1=2\) , not 1.
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Statistics : Posted by Bunuel • on 15 Sep 2014, 23:20 • Replies 7 • Views 61357
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