KarishmaB wrote:
Bunuel wrote:
After a business trip to London, Michele has enough time to visit three European cities before returning home. If she has narrowed her list to six cities that she'd like to visit - Paris, Barcelona, Rome, Munich, Oslo, and Stockholm - but does not want to visit both Oslo and Stockholm on the same trip, how many different sequences of three cities does she have to choose from?
A. 36
B. 48
C. 72
D. 96
E.120
A. 36
B. 48
C. 72
D. 96
E.120
Of the 6 cities, 3 can be selected in 6C3 ways = 20 ways.
Of these, some selections are not acceptable i.e. those in which both Oslo and Stockholm are selected. This selection can be made in 4C1 ways (select Oslo, Stockholm and 1 of the leftover 4 cities)
No of acceptable selections = 20 - 4 = 16
The 3 cities can be arranged in 3! ways to give us total 16 * 3! = 96 sequences
Answer(D)
HiKarishmaB ,
I know it's an old thread but would appreciate your input.
Let's say I don't approach this from a "1-bad choice" approach, but try to sum the good choices.
Why is what
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Statistics : Posted by HaSmamit • on 17 Jul 2016, 07:50 • Replies 11 • Views 6709
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