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Problem Solving (PS) | Re: If x and y are integers and if (x-y)^2 + 2*y^2 ...

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GMATGuruNY wrote:

Bunuel wrote:
GMATGuruNY wrote:
the only possible option for \(y^2\) is 1

__________________
y^2 could also be 9.


Given the answer choices, 9 is not a viable option for \(y^2\) because \(y=±3\) would require that \(x=0\) or \(x=6\), neither of which is among the five options.
I've edited my response to clarify that 1 is one possible option for \(y^2\).
Since this option yields a value for \(x\) that is among the five answer choices, no need to look any further.


Yes, y^2 = 9 does not yield an x value that is among the answer choices, nor was I implying that it does. I was simply pointing out that 1 is not "the only possible option for y^2".

Statistics : Posted by Bunuel • on 25 Nov 2023, 11:06 • Replies 8 • Views 502



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