Vfinal(R)= V(R)(1-m/100)^10 similarly
Vfinal(B)= V(B)(1-n/100)^10
As (1-m/100)^10 will become less than (1-n/100)^10 still V(R) will be rising than V(B) so everytime VFinal(B) will be more than Vfinal(R)
Vfinal(B)= V(B)(1-n/100)^10
As (1-m/100)^10 will become less than (1-n/100)^10 still V(R) will be rising than V(B) so everytime VFinal(B) will be more than Vfinal(R)
Statistics : Posted by bibaswan001 • on 18 Dec 2023, 06:00 • Replies 11 • Views 145
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