MM2008 wrote:
Why do we not get the same result if we do (21*21*5) + (21*5*5) + (5*5*5)
i.e., (2 consonants and 1 vowel OR 1 consonant and 2 vowels OR 3 vowels)?
That approach does not account for the different permutations of the first two cases, so it should be 3*(21*21*5) + 3*(21*5*5) + (5*5*5)
Statistics : Posted by Bunuel • on 03 Jan 2021, 12:50 • Replies 5 • Views 9486
