ruis wrote:
kungfury42 wrote:
Pierre’s European car measures fuel economy in terms of liters per kilometer. If the car averages (1 liter)/(10 kilometers) on a trip, what is the car’s approximate fuel economy in terms of the standard U.S. measurement of miles pergallon ? (Note: 1 gallon is approximately 3.78 liters, and 1 mile is approximately 1.61 kilometers.)
A. 4
B. 16
C. 24
D. 30
E. 40
Given economy\( = 10 kms/L\)
Conversions
\( 1 kms = \frac{1}{1.6} miles\)
\( 1 L = \frac{1}{3.78} gallon\)
Neweconomy
\( =10*\frac{1}{1.6}÷\frac{1}{3.78}\)
\( =10*\frac{3.78}{1.6}\)
\( =\frac{37.8}{1.6}\)
\( \approx{24}miles/gallon\)
Hence, optionC.
Posted from my mobiledevice
A. 4
B. 16
C. 24
D. 30
E. 40
Given economy\( = 10 kms/L\)
Conversions
\( 1 kms = \frac{1}{1.6} miles\)
\( 1 L = \frac{1}{3.78} gallon\)
Neweconomy
\( =10*\frac{1}{1.6}÷\frac{1}{3.78}\)
\( =10*\frac{3.78}{1.6}\)
\( =\frac{37.8}{1.6}\)
\( \approx{24}miles/gallon\)
Hence, optionC.
Posted from my mobiledevice
Why do you work with km/l? Shouldnt it be the opposite? The questions states 1l per 10km.
Apologies in advance for myclumpsiness
1 liter = 10 kilometers
1 gallon = 3.78 liters = 10*3.76 kilometers
1 gallon = 10*3.76 kilometers = 10*3.76/1.61 miles ≈ 10 * 2.4 miles = 24 miles.
Hope it helps.
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Statistics : Posted by Bunuel • on 21 Feb 2022, 01:30 • Replies 3 • Views 1269










