I chose option D because
let x be infected donor and y be total donor. x/3 =y/20(as 55 of actual donor is equal 1/3 of infected donor so from here we get infected donor now constitute 15% of actual donor. Now once the 1/3 of infected donor are qualified the 2/3 of infected donor should be more than 10 % of actual donor as actual donor has decreased.but it remains the same which means the total do or must have remained same. So fulfil the gap the number of 1st time donor must be up by 5% of current actual donor.
let x be infected donor and y be total donor. x/3 =y/20(as 55 of actual donor is equal 1/3 of infected donor so from here we get infected donor now constitute 15% of actual donor. Now once the 1/3 of infected donor are qualified the 2/3 of infected donor should be more than 10 % of actual donor as actual donor has decreased.but it remains the same which means the total do or must have remained same. So fulfil the gap the number of 1st time donor must be up by 5% of current actual donor.
Statistics : Posted by MrMBB • on 27 Jan 2012, 21:11 • Replies 11 • Views 30319









