Problem Solving (PS) | A box contains 20 balls, of which 12 are red and 8 are blue. If two

Number of ways to draw \(1 \) red ball is \( {^{12}}C_1\)

Number of ways to draw \(1\) blue ball is \(^{8}C_1\)

Therefore, total number of ways to draw one red ball and one blue ball \(= {^{12}}C_1 \times {^{8}}C_1\)

\(\textit{Probability} = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\)

­Probability = \(\dfrac{{^{12}}C_1 \times {^{8}}C_1}{{^{20}}C_2} = \dfrac{12 \times 8}{10 \times 19} = \dfrac{48}{95}\)

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Statistics : Posted by meanup • on 29 Mar 2024, 01:30 • Replies 1 • Views 118

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