Official Solution:
\(\sqrt[4]{0.1*0.12*0.123*10^{11}}\) is closest in value to
A. 11
B. 110
C. 121
D. 1100
E. 12,100
\(\sqrt[4]{0.1*0.12*0.123*10^{11}}=\)
\(= \sqrt[4]{1*120*123*10^{4}}=\)
\(= 10\sqrt[4]{120*123} \approx \)
\(\approx 10\sqrt[4]{11^2*11^2}=\)
\(= 10\sqrt[4]{11^4}=\)
\(= 10*11=\)
\(= 110\)
Answer: B
\(\sqrt[4]{0.1*0.12*0.123*10^{11}}\) is closest in value to
A. 11
B. 110
C. 121
D. 1100
E. 12,100
\(\sqrt[4]{0.1*0.12*0.123*10^{11}}=\)
\(= \sqrt[4]{1*120*123*10^{4}}=\)
\(= 10\sqrt[4]{120*123} \approx \)
\(\approx 10\sqrt[4]{11^2*11^2}=\)
\(= 10\sqrt[4]{11^4}=\)
\(= 10*11=\)
\(= 110\)
Answer: B
Statistics : Posted by Bunuel • on 30 Mar 2024, 13:44 • Replies 1 • Views 29
