Its_me_aka_ak wrote:
chetan2u wrote:
\( x^n + x^n + x^n =x^{n+1}........3*x^n=x^n*x.........x^n(3-x)=0\)
Thus either x^n=0 or x=3
What is the value of n?
(1)\( x^n =9\sqrt{3}\)
So x=3as\(x^n\neq{0}\)
So\(3^n=9\sqrt{3}\) ..
We can find n fromit.
\(3^n=9\sqrt{3}=3^{5/2}\) ..n=5/2
(2)\( x =3\)
Insufficient
A
The question should be\(x^n+x^n+x^n=x^{n+1}\)
Thus either x^n=0 or x=3
What is the value of n?
(1)\( x^n =9\sqrt{3}\)
So x=3as\(x^n\neq{0}\)
So\(3^n=9\sqrt{3}\) ..
We can find n fromit.
\(3^n=9\sqrt{3}=3^{5/2}\) ..n=5/2
(2)\( x =3\)
Insufficient
A
The question should be\(x^n+x^n+x^n=x^{n+1}\)
why is st 2 insufficient. i believe n would1 acccording itit
If x = 3, then weget:
\( 3^n + 3^n + 3^n =3^{n+1}\)
\( 3*3^n =3^{n+1}\)
\( 3^{n+1} =3^{n+1}\)
The above is true for any value of n. Hence, (2) is not sufficient.
Hope it's clear.
...
Statistics : Posted by Bunuel • on 09 Dec 2019, 01:30 • Replies 4 • Views 4647
.jpg)
