Nidzo , Check the highlighted portion. I think you made a mistake there. Distance / speed = time...should be (a+b / 60)
poojaarora1818 be careful here. Without knowing anything about the distances one won't be able to solve this question. Just to demonstrate it quickly, I will focus on just statement (1).
From the question stem we know that the average speed for the
...
Nidzo wrote:
poojaarora1818 wrote:
Jim traveled from X to Y, and arrived at Z. If the average speed for the whole trip was 60 miles per hour, what is the average speed for the journey from Y to Z?
(1) The average speed for the trip from X to Y is 55 miles per hour.
(2) It took Jim 0.5 hours from Y to Z.
IMO Option A is the correct one because Average speed is Total Distance/Total time and if the total average speed of the whole trip is 60 miles per hour. According to statement 1, the average speed for the trip from X to Y is 55 miles per hour. So, the average speed for the trip from Y to Z would be 60-55 = 5.
Maybe, optionA
(1) The average speed for the trip from X to Y is 55 miles per hour.
(2) It took Jim 0.5 hours from Y to Z.
IMO Option A is the correct one because Average speed is Total Distance/Total time and if the total average speed of the whole trip is 60 miles per hour. According to statement 1, the average speed for the trip from X to Y is 55 miles per hour. So, the average speed for the trip from Y to Z would be 60-55 = 5.
Maybe, optionA
poojaarora1818 be careful here. Without knowing anything about the distances one won't be able to solve this question. Just to demonstrate it quickly, I will focus on just statement (1).
From the question stem we know that the average speed for the
...
Statistics : Posted by sayan640 • on 09 Apr 2024, 01:30 • Replies 4 • Views 499
