Problem Solving (PS) | ­­When it operates at its own constant rate, hose A can fill an empty

Danou

Given: ­When it operates at its own constant rate, hose A can fill an empty tank twice as fast as hose B can when it operates at its own constant rate.
Asked: If hose A can fill the tank in x hours, how many hours will it take for the two hoses, operating simultaneously, to fill the tank?

Hose B will take 2x hours to fill the empty tank itself
Hose A and Hose B will fill the tank in 1 hour, operating simultaneously = 1/x + 1/2x = 3/2x
Hose A and Hose B operated simultaneously will take = 1/(3x/2) = 2x/3 hours to fill the tank 

IMO A­

Statistics : Posted by Kinshook • on 26 Apr 2024, 21:16 • Replies 3 • Views 116

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