we can solve this by series as number will be in AP with difference of 12 (LCM of 3 &4)
difference=12
first number =108
Last number =996
an=a1+ (n-1) * d
996 = 108 + (n-1) * 12
Solving, we get n=75
difference=12
first number =108
Last number =996
an=a1+ (n-1) * d
996 = 108 + (n-1) * 12
Solving, we get n=75
Statistics : Posted by ravi1522 • on 16 May 2012, 12:04 • Replies 16 • Views 59840
