andrewjohn8 wrote:
Thought I'd add my solution since I believe I didn't see it anywhere.
I factored out the Sqrt(8!) first.
(sqrt(8!(1 + sqrt(9))^2
which reduces to
((sqrt(8!)*(4))^2
8!*16
Then to do the same method as others have shown to get that there are 7 factors of 2 in 8! plus the 4 factors of 2 in 16 means there are at most 11 factors of 2.
That’s good stuff! Very clever
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Statistics : Posted by DanTheGMATMan • on 17 Aug 2023, 03:00 • Replies 14 • Views 13807
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