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GMAT Club Tests | Re: M41-07

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badrinarayanmohan wrote:

­I understand positive sums to positive, but how are you considering a case where x<= 0 and dividing the equation to get 1?

We can have two cass x > 0 or x ≤ 0. As x cannot be positive, it must be less than or equal to 0. According to the absolute value property, when x ≤ 0, then |x| = -x. Thus, we can substitute |x| with -x in the expression we have:

\(\frac{-|x| - 1}{x - 1} = \frac{-(-x) - 1}{x - 1} = \frac{x - 1}{x - 1} = 1\).­

Statistics : Posted by Bunuel • on 21 Apr 2024, 13:52 • Replies 3 • Views 300



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