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Problem Solving (PS) | Re: Three mixtures containing water and milk in ratios of 2:3, 4:5 and 3:4

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sahilsah456 wrote:

Three mixtures containing water and milk in ratios of 2:3, 4:5 and 3:4 are mixed in a proportion of 5:9:14. Find the fraction of the resulting mixture that needs to be replaced with milk for this mixture to contain 75 per cent milk.

A. 37/72
B. 12/19
C. 5/12
D. 53/112
E. 19/76

­Let the three mix be 5, 9 and 14 liters respectively for mixtures containing water and milk in ratios of 2:3, 4:5 and 3:4, then milk will be \(5*\frac{3}{5} + 9*\frac{5}{9} + 14*\frac{4}{7} = 3+5+8 = 16\).

So, 16 out of 5+9+14 or 28 liters is milk. But we require milk to be 75% of 28 or 21 liters.

So we have to replace 5 liters of water by milk as whatever is the proportion of milk that is removed is filled back by milk.
Thus, 5/12 of mixture would mean 5/12 of water + 5/12 of milk.­

Statistics : Posted by chetan2u • on 10 Jul 2024, 04:37 • Replies 4 • Views 148



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