GMAT Problem Solving (PS) | The circle above has 6 points on its edge. How many different triangle

Any 3 points (of the points forming a circle) can form a traingle.

Here we have specific 6 points => 6c3 (combinations because any order can be taken)
=>\(\frac{6!}{(6-3)!3!}\)
=>\( \frac{6*5*4*3!}{3!*(3*2)} \)
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