Bunuel wrote:
If \(\sqrt{x}=y\), what is the value of \(\sqrt{x}\)?
(1) 35 – y is an integer.
(2) 101 < x < 143
(1) 35 – y is an integer.
This one tells us that x is also an integer, but it does give us the value of x. 35 - 11, 35 - 9 ... y can take any value from o to 35 Insuficient.
(2) 101 < x < 143
This one tell about the rang of x values but does no tell us about whether x is an integer or not.
\(x = 11^2= 121\) or\( x =\frac{23^2}{2^2} = 132\frac{1}{4} \)
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