ziyuenlau wrote:
GMATPrepNow wrote:
GMATPrepNow wrote:
A box contains 1 blue ball, 1 yellow ball, and 2 red balls.
Three balls are randomly selected (one after the other) without replacement.
What is the probability that the 2nd ball is yellow or the 3rd ball is NOT yellow?
A) 1/2
B) 3/4
C) 5/6
D) 11/12
E) 1
Three balls are randomly selected (one after the other) without replacement.
What is the probability that the 2nd ball is yellow or the 3rd ball is NOT yellow?
A) 1/2
B) 3/4
C) 5/6
D) 11/12
E) 1
First of all, it's useful to recognize that P(2nd ball is yellow or the 3rd ball is NOT yellow) is the SAME as P(1st ball is yellow or the 2nd ball is NOT yellow)
Let's apply the OR probability rule: P(A or B) = P(A) + P(B) - P(A and B)
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