If 1 male, 2 females, and 1 child are to be randomly selected from 8 males, 10 females, and 8 children, how many such cases are possible?
A. 980 B. 1,440 C. 1,880 D. 2,480 E. 2,880
==> You get 8C1*10C2*8C1=(8)(45)(8)=2,880.
The answer is E.
Answer: E
A. 980 B. 1,440 C. 1,880 D. 2,480 E. 2,880
==> You get 8C1*10C2*8C1=(8)(45)(8)=2,880.
The answer is E.
Answer: E
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