\((x-y)^2=?\)
1) x and y are integers
2) xy=3
==> In the original condition, there are 2 variables (x, y) and in order to match the number of variables to the number of equations, there must be 2 equations. Since there is 1 for con 1) and 1 for con 2), C is most likely to be the answer. By solving con 1) and con 2), you get (x,y)=(1,3),(3,1),(-1,-3),(-3,-1), and all become\((x-y)^2=4\) , hence it is unique and sufficient.
Therefore, the answer is C.
Answer: C
...
1) x and y are integers
2) xy=3
==> In the original condition, there are 2 variables (x, y) and in order to match the number of variables to the number of equations, there must be 2 equations. Since there is 1 for con 1) and 1 for con 2), C is most likely to be the answer. By solving con 1) and con 2), you get (x,y)=(1,3),(3,1),(-1,-3),(-3,-1), and all become\((x-y)^2=4\) , hence it is unique and sufficient.
Therefore, the answer is C.
Answer: C
...
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