Quantcast
Channel: GMAT Club Forum - Forums > Reading Comprehension (RC)
Viewing all articles
Browse latest Browse all 291973

GMAT Problem Solving (PS) | Re: A committee of 3 people is to be chosen from four married

$
0
0
I solved it using this method, hope I'm using the correct concept

total 4 couples = 8 people in total
total no of ways to choose 3 people out of 8 = 8!/(5!3!) = 56
No. of ways couples are included in the com = 4! = 24
Therefore no. of couples with no couples included = 56-24 = 32.

Viewing all articles
Browse latest Browse all 291973

Trending Articles



<script src="https://jsc.adskeeper.com/r/s/rssing.com.1596347.js" async> </script>