I solved it using this method, hope I'm using the correct concept
total 4 couples = 8 people in total
total no of ways to choose 3 people out of 8 = 8!/(5!3!) = 56
No. of ways couples are included in the com = 4! = 24
Therefore no. of couples with no couples included = 56-24 = 32.
total 4 couples = 8 people in total
total no of ways to choose 3 people out of 8 = 8!/(5!3!) = 56
No. of ways couples are included in the com = 4! = 24
Therefore no. of couples with no couples included = 56-24 = 32.