I did analyse the problem by prime factorization.
1)
\(15*z\)
\(15=3*5\) and \(22=2*11\), therefore z must have a factor of 2
2)
\(16*z\)
\(16=2^4\) and \(22=2*11\), as 16 has already a factor of 2, we can't be sure that z has also a factor of 2
1)
\(15*z\)
\(15=3*5\) and \(22=2*11\), therefore z must have a factor of 2
2)
\(16*z\)
\(16=2^4\) and \(22=2*11\), as 16 has already a factor of 2, we can't be sure that z has also a factor of 2
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