Bunuel wrote:
The average (arithmetic mean) of 3 consecutive prime numbers is 41/3. Which of the following is the largest of the three consecutive primes?
A. 5
B. 11
C. 13
D. 17
E. 19
We are given that the average (arithmetic mean) of 3 consecutive prime numbers is 41/3 = 13 ⅔. Thus, within our set of consecutive prime numbers, we must find values that are less than 13 ⅔ and also greater. Thus, we see that neither 5, nor 11, nor 13 can be the greatest of the 3 consecutive prime numbers. Let’s start
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