IMOD
\(a^6 = b^3 = \frac{|x|}{x}\)
\(\frac{|x|}{x}\) = 1 or -1 depending on the sign of x,but since this fraction is equal to\(a^6\) ,it has to be equal to 1.
Therefore x=some postive,b =1 and a =+1 or -1 => a-b=0 or a-b=-2 depending on the value of a.
statement1:
\(a^3b^7\) >0,
since b=1, \(a^3\) >0, not possible for this statment.
therefore a>0 => a=1.
a-b=0
statement 2:
a+b >0 ,
if a=-1,then a+b=0. Therefore a=1.
a-b=0.
Both the statement satisfies ,so D.
...
\(a^6 = b^3 = \frac{|x|}{x}\)
\(\frac{|x|}{x}\) = 1 or -1 depending on the sign of x,but since this fraction is equal to\(a^6\) ,it has to be equal to 1.
Therefore x=some postive,b =1 and a =+1 or -1 => a-b=0 or a-b=-2 depending on the value of a.
statement1:
\(a^3b^7\) >0,
since b=1, \(a^3\) >0, not possible for this statment.
therefore a>0 => a=1.
a-b=0
statement 2:
a+b >0 ,
if a=-1,then a+b=0. Therefore a=1.
a-b=0.
Both the statement satisfies ,so D.
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