nishantd88 wrote:
SajjadAhmad wrote:
If a = 1,248 and b = 1,152, what is the value of (a^2 + b^2) ^\(\frac{1}{2}\)?
A. 240
B. 360
C. 480
D. 600
E. 720
A. 240
B. 360
C. 480
D. 600
E. 720
Is there any way to solve this other than doing a long multiplication?
(a^2 + b^2) can be replaced by (a+b)^2-2ab. But still one long multiplication has to bedone
Hi, you don't need to do the multiplication of numbers. Do it like this,
(a^2-b^2)^1/2 =[(a-b)(a+b)] ^1/2
(a-b) =2400
(a+b)=96
Now start taking perfect squares out of square root. Start with 2400, we get 24*100 where 100^1/2 = 10
So
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