Hi Bunnel,
I don't know if I got lucky but I did this.
Let the cost of first car be x and second be y.
The profit from first car be 0.1x and loss from second be 0.1y.
now it is obvious that the profit of first car is higher than the loss of second car as we are getting a profit of 1000.
Now we know the total profit will be 0.1x-0.1y=1000
=>x-y=10000 and there is only one answer which gives x-y as 10000 that is D.
Regards,
Arpan
I don't know if I got lucky but I did this.
Let the cost of first car be x and second be y.
The profit from first car be 0.1x and loss from second be 0.1y.
now it is obvious that the profit of first car is higher than the loss of second car as we are getting a profit of 1000.
Now we know the total profit will be 0.1x-0.1y=1000
=>x-y=10000 and there is only one answer which gives x-y as 10000 that is D.
Regards,
Arpan









