Bunuel wrote:
If \(\frac{x + y}{x − y} = \frac{1}{2}\), then \(\frac{xy + x^2}{xy − x^2}=\)
(A) –4.2
(B) –1/2
(C) 1.1
(D) 3
(E) 5.3
Taking x as common from the fraction; \(\frac{xy + x^2}{xy − x^2}\)
\(\frac{x(y + x)}{x(y - x)}\)
Cancelling out "x" we get =\(\frac{x+y}{-(x-y)}\)
Given;\(\frac{x + y}{x − y} = \frac{1}{2}\)
Therefore ;\(\frac{x+y}{-(x-y)}\) = -\(\frac{1}{2}\)
Answer B...
...
![FLO – Therapy at the Club – Pre-Single [iTunes Plus M4A]](http://is1-ssl.mzstatic.com/image/thumb/Music221/v4/a4/11/88/a41188ed-0f2e-e8d5-1163-d59e373cc58c/26UMGIM30046.rgb.jpg/208x208bb.webp)
