Bunuel wrote:
If \(3^x = 81\), then \(3^{(x+3)}*4^{(x+1)} =\)
(A) 5*7^5
(B) 9*7^5
(C) 2^12^4
(D) 9*12^5
(E) 2*12^7
\(3^x = 81 = 3^4\)
i.e. x=4
\(3^{(x+3)}*4^{(x+1)} =3^7*4^5 = 3^2*(4*3)^5 = 9*12^5\)
Answer: Option D
If \(3^x = 81\), then \(3^{(x+3)}*4^{(x+1)} =\)
(A) 5*7^5
(B) 9*7^5
(C) 2^12^4
(D) 9*12^5
(E) 2*12^7
\(3^x = 81 = 3^4\)
i.e. x=4
\(3^{(x+3)}*4^{(x+1)} =3^7*4^5 = 3^2*(4*3)^5 = 9*12^5\)
Answer: Option D
