ratinarace wrote:
let me ask a lame question...
x^2-8x+21=|x-4|+5
x^2-8x+21-5=|x-4|
x^2-8x+16=|x-4|
(x-4)(x-4)=|x-4|
Now Scenario 1 where |x-4| is positive
(x-4)(x-4)=(x-4)
(x-4) = (x-4)/(x-4) ------> (x-4)=1-----> x = 5
Scenario 2 where |x-4| is negative
(x-4)(x-4)=-(x-4)---------> (x-4)=-(x-4)/(x-4)----------> (x-4)=-1--------> x = 3
So i have only two solutions x=5 and x=3...Why am I getting only 2 solutions ? while there are 3...
I know I am doing something very stupid with the basics.
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