BANON wrote:
If x, y, and k are positive numbers such that (x/(x+y))(10) + (y/(x+y))(20) = k and if x < y, which of the following could be the value of k?
A. 10
B. 12
C. 15
D. 18
E. 30
We are given:
(x/(x+y))(10) + (y/(x+y))(20) = k
[10x/(x+y)] +[20y/(x+y)] = k
We can combine the two fractions on the left side of the equation because they have the same denominator, (x + y).
[(10x + 20y)/(x+y)] = k
We see that we have a weighted average equation in which x items have an average of 10, and another y items have an
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