gmatraider wrote:
If each of the following fractions were written as a repeating decimal, which would have the longest sequence of different digits?
A) 2/11
B) 1/3
C) 41/99
D) 2/3
E) 23/37
If a fraction (in lowest terms) can be written as a repeating decimal and the number of decimal digits repeating is n, then the denominator must be a factor of 10^n - 1.
For example, 1/3 (in choice B) has a denominator of 3, which is a factor of 9 = 10^1 - 1 = 9; thus, 1/3 has 1 decimal digit repeating. Sure enough, 1/3 =
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