AR15J wrote:
Hi Bunuel,
Why is the below approach incorrect?
6c1*1*4c1*1/(4!*6c4) Firstly, we are selecting one sock out of 6, then we can select second in just one way as we are assuming that it is the second sock of the pair and so on; since the combination can be any so divide by 4! and total cases are 6c4.
HiJeffTargetTestPrep ,
Can you please suggest why my approach is incorrect?
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