\(x > y > 0\) and\(p > q > 0\)
There two ways with which you can solve this question:
1. Test some values
2. Leverage and solve given information
I will solve by the second method considering it is easy and takes less time.
As -\(x > y > 0\)
and\(p > q > 0\) we can write -
\(x > y\)
\(p> q\)
\(x + p > y + q\)
\(\frac{x + p}{y + q} > 1\) - Dividing both the sides by\(y+q\)
So, without even checking the values we have go the equation which matches tho the first one.
Hence, the answer is A
...
There two ways with which you can solve this question:
1. Test some values
2. Leverage and solve given information
I will solve by the second method considering it is easy and takes less time.
As -\(x > y > 0\)
and\(p > q > 0\) we can write -
\(x > y\)
\(p> q\)
\(x + p > y + q\)
\(\frac{x + p}{y + q} > 1\) - Dividing both the sides by\(y+q\)
So, without even checking the values we have go the equation which matches tho the first one.
Hence, the answer is A
...




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