\(y^3 < |y|\)
(1)\(y < 1\)
Consider\(y = \frac{1}{2}\)
\({\frac{1}{2}}^3 < {|\frac{1}{2}|}\)
\({\frac{1}{8}} < {\frac{1}{2}}\) ==> TRUE
Lets check for ZERO aswell
\({0}^3 ≤ |0| = 0 = 0\) ==> FALSE
Now, lets check for Negative values as well, as we know that mod/absolute function will always give us positive values and cube of negative will always give us negative values, our L.H.S. Should always be < R.H.S. Lets test
\({\frac{-1}{2}}^3 < {|\frac{-1}{2}|}\)
\( {\frac{-1}{8} } <{\frac{1}{2} } \)
...
(1)\(y < 1\)
Consider\(y = \frac{1}{2}\)
\({\frac{1}{2}}^3 < {|\frac{1}{2}|}\)
\({\frac{1}{8}} < {\frac{1}{2}}\) ==> TRUE
Lets check for ZERO aswell
\({0}^3 ≤ |0| = 0 = 0\) ==> FALSE
Now, lets check for Negative values as well, as we know that mod/absolute function will always give us positive values and cube of negative will always give us negative values, our L.H.S. Should always be < R.H.S. Lets test
\({\frac{-1}{2}}^3 < {|\frac{-1}{2}|}\)
\( {\frac{-1}{8} } <{\frac{1}{2} } \)
...




