The only contents of a parcel are 25 photographs and 30 negatives. What is the total weight, in ounces, of the parcel's contents?
(1) The weight of each photograph is 3 times the weight of each negative.
\(p = 3n\)
\(25(3n) + 30n = 75n + 30n = 105n\)
As we are not aware of the value of n we cannot determine the total weight.
Hence, (1) =====> is NOT SUFFICIENT
(2) The total weight of 1 of the photographs and 2 of the negatives is 1/3 ounce.
\( 1p + 2n =\frac{1}{3} \)
...
(1) The weight of each photograph is 3 times the weight of each negative.
\(p = 3n\)
\(25(3n) + 30n = 75n + 30n = 105n\)
As we are not aware of the value of n we cannot determine the total weight.
Hence, (1) =====> is NOT SUFFICIENT
(2) The total weight of 1 of the photographs and 2 of the negatives is 1/3 ounce.
\( 1p + 2n =\frac{1}{3} \)
...




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