ManSab wrote:
There are x teams and each team plays each other once. If there was one less team, there would be 3/4 as many games. What is the value of x?
A)9
B)8
C)7
D)6
E)5
The number of games played if there are x teams is xC2 and the number of games played if there were one less team would be (x-1)C2. Thus, we can create the following equation:
(x-1)C2 = ¾ * xC2
(x - 1)(x - 2)/2 =¾[x(x - 1)/2]
x - 2 = ¾(x)
4(x - 2) = 3x
4x - 8 = 3x
x = 8
Answer: B
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