MathRevolution wrote:
If x=2y=4z for positive integers x, y, and z, which of the following can be the average (arithmetic mean) of x, y and 3z?
A. 15
B. 20
C. 25
D. 40
E. 47
Let, x=2y=4z = 4
So, x = 4 , y = 2 & z = 1
Arithmetic Mean of x, y & 3z is\(\frac{4 + 2 + 3}{3} = 3\)
So, The number must be a multiple of 3, only (A) satisfies, thus answer will be (A) 15
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